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x^2+10+5x-6=180
We move all terms to the left:
x^2+10+5x-6-(180)=0
We add all the numbers together, and all the variables
x^2+5x-176=0
a = 1; b = 5; c = -176;
Δ = b2-4ac
Δ = 52-4·1·(-176)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*1}=\frac{-32}{2} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*1}=\frac{22}{2} =11 $
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